Graphical Solution for Angular Velocity in a Four-Bar Chain

By user , 17 November 2025

Problem Statement

In a Four-bar chain ABCD, AD is fixed and is 150 mm long. The crank AB is 40 mm long and rotates at 120 r.p.m. clockwise, while the link CD = 80 mm oscillates about D. BC and AD are of equal length. Find the angular velocity of link CD when angle ∠BAD = 60°.


1. Given Data and Initial Calculations

LinkLength (m)Other Data
Fixed Link (AD)LAD = 0.15 mNAB = 120 r.p.m. (CW)
Crank (AB)LAB = 0.04 m∠BAD = 60°
Coupler (BC)LBC = 0.15 m 
Rocker (CD)LCD = 0.08 m 
four-bar-chain-abcd-ad-fixed-and-150-mm-long-crank-ab-40-mm-long-and-rotates-120-rpm-clockwise-while

 

Analytical Calculations (Crank AB)

**1. Angular Velocity of Crank AB (ωAB):** ωAB = (2 π NAB) / 60 
ωAB = (2 π × 120) / 60 = 4 π rad/s ≈ 12.57 rad/s 

**2. Linear Velocity of Point B (VB):** VB = ωAB × LAB 
VB = 12.57 rad/s × 0.04 m = 0.5028 m/s 


2. Calculation of Angular Velocity (ωCD)

Assuming the linear velocity of C (VC) is found graphically, the final angular velocity of link CD (ωCD) is calculated using the relationship:

 

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