Problem Statement
In a Four-bar chain ABCD, AD is fixed and is 150 mm long. The crank AB is 40 mm long and rotates at 120 r.p.m. clockwise, while the link CD = 80 mm oscillates about D. BC and AD are of equal length. Find the angular velocity of link CD when angle ∠BAD = 60°.
1. Given Data and Initial Calculations
| Link | Length (m) | Other Data |
|---|---|---|
| Fixed Link (AD) | LAD = 0.15 m | NAB = 120 r.p.m. (CW) |
| Crank (AB) | LAB = 0.04 m | ∠BAD = 60° |
| Coupler (BC) | LBC = 0.15 m | |
| Rocker (CD) | LCD = 0.08 m |

Analytical Calculations (Crank AB)
**1. Angular Velocity of Crank AB (ωAB):** ωAB = (2 π NAB) / 60
ωAB = (2 π × 120) / 60 = 4 π rad/s ≈ 12.57 rad/s
**2. Linear Velocity of Point B (VB):** VB = ωAB × LAB
VB = 12.57 rad/s × 0.04 m = 0.5028 m/s
2. Calculation of Angular Velocity (ωCD)
Assuming the linear velocity of C (VC) is found graphically, the final angular velocity of link CD (ωCD) is calculated using the relationship:
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