## State the reason of using roller follower over kinfe edge follower.

1) Roller follower has less wear and tear than knife edge follower.

2) Power required for driving the cam is less due to less frictional force between cam and

follower.

Reverse Engineering the exam question papers

1) Roller follower has less wear and tear than knife edge follower.

2) Power required for driving the cam is less due to less frictional force between cam and

follower.

1) Acceleration diagram is important in mechanism , because acceleration is directly related to

force. F = m * a

2) By calculating acceleration, we calculate inertia force acting on different links.

3) Design of machine parts rotating at higher speed becomes safe.

1)Completely constrained motion :- When the motion between a pair is limited to a definite

direction irrespective of the direction of force applied, then the motion is said to be a completely

constrained motion.

2)Successfully constrained motion:- When the motion between the elements, forming a pair, is

such that the constrained motion is not completed by itself, but by some other means, then the

motion is said to be successfully constrained motion.

1) Link 1 and 2 -- Sliding Pair

2) Link 2 and 3 -- Turning Pair

3) Link 3 and 4 -- Turning Pair

4) Link 4 and 1 -- Sliding pair

The weights of four masse A, B, C, D are 200 Kg, 300 Kg, 240 Kg and 260 Kg

respectively. The corresponding radii of rotation are 200 mm, 150 mm, 250 mm and

300 mm respectively and the angle between successive masses are 45o, 75o and

135o. Find the position and magnitude of the balance weight required if its radius of

rotation is 200 mm.

OR

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Draw the constructional details diagram of Centrifugal clutch. Explain its working principle.

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Two pulleys one 450 mm diameter and the other 200 mm diameter are on parallel shafts 1.95

m apart and are connected by a crossed belt. Find the length of belt required and angle of

contact between belt and each pulley. Estimate the power transmitted by belt when the

larger pulley rotates at 200 rpm. If the maximum tension in the belt is 1 KN and coefficient of

friction between belt and pulley is 0.25.

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Explain the following terms of centrifugal governor with neat sketch:

(i)Height of Governor

(ii)Equilibrium Speed

(iii)Sleeve Lift

Terms related with Governor:

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A 4-bar mechanism has following dimensions:

l(DA) = 300 mm, l(CB) = l(AB) = 360mm, l(DC) = 600 mm. the link ‘DC’ is fixed. The

angle ADC is 60o. The driving link ‘DA’ rotates at a speed of 100 rpm clockwise and

constant driving torque is 50 N-m. Calculate the velocity of point ‘B’ and angular

velocity of driven link ‘CB’.

Given Data:

N AD = 100 rpm

DA = 300 mm = 0.3 m

T A = 50 N-m

ω AD = 2 π x 100 /60 = 10.47 rad/sec.

Velocity of A w.r.t. D (V AD);

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Two parallel shafts whose centre lines are 4.8 m apart are connected by open belt

drive. The diameter of larger pulley is 1.5 m and that of smaller pulley 1 m. the initial

tension in the belt when stationary is 3 KN. The mass of the belt is 1.5 Kg/m length.

The coefficient of friction between belt and pulley is 0.3. Taking centrifugal tension

in to account, calculate power transmitted when smaller pulley rotates at 400 rpm.

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